1.

A block moves down a smooth plane of inclination theta. Its velocity on reaching the bottom is v. If it slides down a rough inclined plane some inclination, its velocity on reaching the bottom is v/n, where n is a number greater than 0. The coefficient of friction is given by:

Answer»

`mu = tan THETA (1- 1/n^(2))`
`mu = COT theta (1-1/n^(2))`
`mu = tan theta (1- 1/n^(2))^(1//2)`
`mu = cot theta (1- 1/n^(2))^(1//2)`

Solution :`v^(2) = 2g SIN theta xx l`
`v^(2)/n^(2) = 2(G sin theta - mu g costheta)l`
`sin theta(1-1/n^(2)) = mu cos theta`
`mu = tan theta (1-1/n^(2))`


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