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A block of mass 0.50 kg is moving with a speed of2.0 m s^(-1) on a smooth surface. It strikes another stationary block of mass 1.0 kg and then move together as a single body. The energy loss during the collision is |
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Answer» 0.16 J =Momentum before collision , `(m_1+m_2)V=m_1u_1+m_2u_2` (0.5 +1.0)v = 0.5 x 2.0 + 1.0 x 0 `v=1/1.5=2/3 m s^(-1)` Loss of ENERGY ,= `1/2m_1u_1^2-1/2(m_1+m_2)v^2`=0.67 J |
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