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A block of mass 1 kg is suspended by a string of mass 1 kg, length1m as shown in figure. (g 10 m/s?) Calculate: [15JP110728](a) the tension in string at its lowest point.(b) the tension in string at its mid-point.(c) force exerted by support on string.dad (rom tho ceiling by a light string, A second block of ma |
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Answer» According to given question the block and string have same mass = 1kg and length of string is 1metre (taking g =10m/s2) now the tension in the string at the lowest point is only due to block of mass 1 kg T = mg = 1 x10 = 10 N. B> the tension at middle is due to string and the blockand total mass = (1+0.5) kg (since at middle the mass of string gets half) hence tension at middle is = 1.5 x 10 = 15N C > now tension at support is due to combined mass of string and block Total mass = 1+1 = 2kg Tension = 2 x10 =20NHence 10,15, 20 are the tensions in the string at differnet positions. |
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