1.

A block of mass 2 kg is dropped from a height of 0-4 mon a spring whose force constant is 1960 N/m. What will be the maximum distance x of the compression of the spring ?

Answer»

0.5 m
0.1 m
0.01 m
1 m

Solution :P.E. of spring = LOSS in P.E. of body
`1/2 kx^(2)=mg(h+X)`
`2(0.4+x)9.8=(1)/(2)1960xxx^(2)`
`19.6(0.4+x)=980 x^(2)`
Which gives on SOLVING, the quadratic `x=(1)/(10)=0.1 m`


Discussion

No Comment Found

Related InterviewSolutions