A block of mass 200 g is suspended by a vertical spring. The spring is stretched by 1.0 cm when the block is in equilibrium. A particle of mass 120 g is dropped on the block from a height of 45 cm. The particle sticks to the block after the impact. Find the maximum extension of the spring. Take g = 10 m//s^(2).

A block of mass 200 g is suspended by a vertical spring. The spring is

1.	A block of mass 200 g is suspended by a vertical spring. The spring is stretched by 1.0 cm when the block is in equilibrium. A particle of mass 120 g is dropped on the block from a height of 45 cm. The particle sticks to the block after the impact. Find the maximum extension of the spring. Take g = 10 m//s^(2).
Answer» ANSWER :5 CM

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