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A block of mass `2kg` is propped from a heught of `40cm` on a spring where force constant is `1960Nm^(-1)` The maximum distance thought which the spring compressed byA. 5 cmB. 15 cmC. 20 cmD. 10 cm |
Answer» Correct Answer - D `mg(h+x)=1/2kx^2` Here, m= 2 kg, h=40 cm `k=1960 N m^(-1) and g=10 m s^(-2)` `therefore 2 xx 10 (0.40+x)=1/2xx1960 x^2` On solving , we get x = 10 cm |
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