A block of mass 3 kg slides down an inclined plane of length 6 m and height 4 m. if the force of friction on the block is a constant 16 N as it slides from rest at the top of the incline, what is its speed at the bottom?

A block of mass 3 kg slides down an inclined plane of length 6 m and h

1.	A block of mass 3 kg slides down an inclined plane of length 6 m and height 4 m. if the force of friction on the block is a constant 16 N as it slides from rest at the top of the incline, what is its speed at the bottom?
Answer» 2m/s 3m/s 4m/s 5m/s Solution :Apply conservation of mechanical energy (including the negative work done by `F_(P)` the force of sliding friction). `K_(i)+U_(i)+W_("frict")=K_(F)+U_(f)` `0+mgh-F_(f)L=(1)/(2)mv^(2)+0` `v=sqrt((2)/(m)(mgh-F_(f)L))` `=sqrt((2)/(3)(3xx10xx4-16xx6))` `=sqrt(16)` `=4m//s` NOTE: `W_("total")=DeltaK` could also be used.

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A block of mass 3 kg slides down an inclined plane of length 6 m and height 4 m. if the force of friction on the block is a constant 16 N as it slides from rest at the top of the incline, what is its speed at the bottom?

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