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A block of mass 4 kg is placed on a rough horizontal plane. A time dependent horizontal force F = kt acts on the block (k = 2 N//s). Find the frictional force between the block and the plane at t = 2 second and t = 5 second (mu=0.2) |
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Answer» Solution :When t = 2 sec F = 4N `f_(ms)=mu_(s)MG =0.2xx4xx10=8N` `therefore F lt f_(ms) therefore`FRICTION = 4N When t = 5 sec F = 2 (5) = 10 N `F GT f "" therefore` friction = 8 N |
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