A block of mass 4 kg is placed on the floor. The coefficient of static friction is 0.4. If a force of 12 N is applied on the block parallel to the floor, the force of friction between the block and floor (g = 10 ms^(-2))

A block of mass 4 kg is placed on the floor. The coefficient of static

1.	A block of mass 4 kg is placed on the floor. The coefficient of static friction is 0.4. If a force of 12 N is applied on the block parallel to the floor, the force of friction between the block and floor (g = 10 ms^(-2))
Answer» zero 8N 12N 16 N Solution :Force of limiting friction, `F_(f)= m_(s) MG` `F_(f) = 0.4 xx 4 xx 10 = 16 N` Since applied force 12 N is less than limiting friction therefore, force of friction will be 12 N as friction will be 12 N as friction is a SELF adjusting force upon `F_(f)` Hence correct CHOICE is (c)

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A block of mass 4 kg is placed on the floor. The coefficient of static friction is 0.4. If a force of 12 N is applied on the block parallel to the floor, the force of friction between the block and floor (g = 10 ms^(-2))

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