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InterviewSolution
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A block of mass `m=2kg ` is pulled by a force `F=40 N` upwards through a height `h=2 m.` Find the work done on the block by the applied force `F` and its weight mg. `(g=10m//s^2)`. |
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Answer» Weight of the block, `mg=(2)(10)=20N` Work done by the applied force, `W_(F) = Fs cos theta = Fh cos 0^(@)` (Here,s=h=2m and angle between force and displacement is `0^(@))` or ` W_(F)=(40)(2)(1)=80 J` Similarly, work done by its weight , `W_(mg)=(mg)(h) cos180^(@)` or `W_(mg)=(20)(2)(-1)=-40 J` |
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