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A block of mass M=4kg is moving with velocity V=6m/s toward a target block of mass=2kg, which is stationary (v=0). The object collide heat-on, and immediately after the collision, the speed of block m is 4 times the speed of block M. Q. What is the speed of block M after the collision? |
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Answer» Solution :If we let V' be the SPEED of block M immediately after the COLLISION, then the speed of block m will be 4V'. By applying conservation of linear momentum, we FIND that TOTAL `p_("before")=`total`p_("after")` `MV=MV'+m(4V')` `(4)(6)=(4)(V')+(2)(4V')` `V'=2m//s` Therefore, the speed of block M immediately after the collision is 2m/s (and the speed of block m immediately after the collision is 8 m/s). |
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