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A block of mass m is placed on a surface with a vertical cross section given by y =(x^(3))/(6)If the coefficient of friction is 0.5, the maximum height above the ground at which the block can be placed without slipping is : |
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Answer» `(1)/(2)m` `:. y =(x^(3))/(6)`(vol. of one) At the POINT of just SLIDING `MG SIN theta = umg cos theta` `tan theta=mu,(dy)/(dx) = tan theta=mu=(1)/(2), (x^(2))/(2) =(1)/(2),.y =(x^(3))/(6)` m. `:.y=1//6m` 
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