1.

A block of mass m rests on a platform. Theplatform is given up and down S.H.M. withan amplitude d. What can be themaximum frequency so that the block never leaves the platform ?

Answer»

`sqrt(g//d)`
`(1)/(2pi)sqrt((g)/(d))`
`(1)/(2pi)((g)/(d))`
`(1)/(2pi)sqrt((g)/(d))`.

Solution :For block to remain in contact `a_("MAX")=g`.
`:.""OMEGA^(2)d=gimplies4pi^(2)vd=g`
`v=(1)/(2pi)sqrt(g//d)`
Hence correct CHOICE is (B).


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