1.

A block of mass m sliding down an incline plane. The incline plane has fixed base length 'l' and coefficient of friction on the inclineplane is 'mu'. The plane is fixed and block slides from top to bottom. Let theta_(0) be the inclination angle for minimum sliding time and v_(0) be the block's speed when it reaches the bottom in that case. Pick the correct option (s):

Answer»

`v_(0)=sqrt(2gl(tantheta_(0)-MU))`
`v_(0)=sqrt(2gl tantheta_(0))`
`tan(2theta_(0))=(-1)/(mu)`
`tan(theta_(0))=1/(mu)`

Solution :`t^(2)=(2l)/(g[cos alpha SIN alpha -mu cos^(2) alpha])`
For min. time, `d/(dalpha)(cosalpha sin alpha-mucos^(2)alpha)=0`
`IMPLIES tan 2ALPHA =(-1)/(mu)`
`/_\K+/_\U=W_("friction")`
`impliesv_(0)=sqrt(2gl(tantheta_(0)-mu))`


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