InterviewSolution
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InterviewSolution
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A block of mass `m`, when attached to a uniform ideal apring with force constant `k` and free length `L` executes SHM. The spring is then cut in two pieces, one with free length n `L` and other with free length `(1 - n)L`. The block is also divided in the same fraction. The smaller part of the block attached to longer part of the spring executes SHM with frequency `f_(1)` . The bigger part of the block attached to smaller part of the spring executes SHM with frequency `f_(2)`. The ratio `f_(1)//f_(2)` isA. `1`B. `(n)/(1 - n)`C. `(1 + n)/(n)`D. `(n)/(1 + n)` |
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Answer» Correct Answer - A `k prop (1)/("Length of spring")` `{:("Length","Force constant"),(L,k),(nL,k//n),((1-n),k//(1-n)):}` `m_(1) = nm` and `m_(2) = (1 - n)m` `(f_(1))/(f_(2)) = ((1)/(2pi)sqrt ((k//n)/((1 - n)m)))/((1)/(2pi)sqrt((k//(1 - n))/(nm))) = 1` |
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