1.

A block of weight W rests on horizontal floor with coefficient of static friction mu . It is desired to make the block move by applying minimum amount of force. The angle theta from the horizontal at which the force should be applied and the magnitude F of the force is

Answer»

`THETA = 0, F= mu W`
`theta = tan^(-1) (mu), F = (mu W)/(sqrt(1 + mu^2))`
`theta = tan^(-1) (1/mu), F = (mu W)/(sqrt(1 + mu^2))`
`theta = tan^(-1)((mu)/(1 + mu)) , F = (mu W)/(1 + mu^2)`

ANSWER :B


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