1.

A block of wood floats with 1//4 of its volume under water. What is he density of wood? (Density of water =1000 kg //m^(3))

Answer»

`750 kg//m^(3)`
`250 kg//m^(3)`
`300 kg//m^(3)`
`260 kg//m^(3)`

Solution :(b) LET the volume of wood piece is `V_(0)`
The DIPPED PORTION of he piece is
`V(V_(0))/(4)`
`:.` For EQUILIBRIUM of wood piece,
`mg=rhoVg`
or `sigma C_(0)g=(rhoC_(0))/(4)g`
`:.Sigma =(rho)/(4)=("DENSITY of water")/(4)`
`=(1000)/(4)=250 kg//m^(3)`


Discussion

No Comment Found

Related InterviewSolutions