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A block slides down a frictionless, inclined plane that makes a 30^(@) angle with the horizontal. Find the acceleration of this block. |
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Answer» Solution :Let m be the MASS of the BLOCK, so the force that pulls the block down the incline is `mg sin theta`, and the block's acceleration down the plane is `a= (F)/(m)=(mg sin theta)/(m)= g sin theta= g sin 30^(@)=(10)xx(0.5)=5 m//s^(2)` |
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