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A boat which has a speed of 5 km h^(-1) in still water crosses a river of width 1 km along the shortest possible path in 15 minutes. The velocity of the river water in km h^(-1) is

Answer»

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`sqrt41`

Solution :Resultant velocity of boat, `v="1 KM"/"15 MIN"`
`="1 km"/"(1/4) h"=4"km h"^(-1)`
Velocity of RIVER, `v_R=sqrt(v_B^2-v^2)=sqrt(5^2-4^2)=3 "km h"^(-1)`


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