A bob of a simple pendulum of mass 40 mg with a positive charge 4 xx 10^(-6)Cis oscilliating with time period "T_(1). An electric field of intensity 3.6 xx 10^(4) N/c is applied vertically upwards now time period is T_(2). The value of (T_(2))/(T_(1)) is (g = 10 m/s^(2))

A bob of a simple pendulum of mass 40 mg with a positive charge 4 xx 1

1.	A bob of a simple pendulum of mass 40 mg with a positive charge 4 xx 10^(-6)Cis oscilliating with time period "T_(1). An electric field of intensity 3.6 xx 10^(4) N/c is applied vertically upwards now time period is T_(2). The value of (T_(2))/(T_(1)) is (g = 10 m/s^(2))
Answer» 0.16 0.64 1.23 0.8 Answer :C

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A bob of a simple pendulum of mass 40 mg with a positive charge 4 xx 10^(-6)Cis oscilliating with time period "T_(1). An electric field of intensity 3.6 xx 10^(4) N/c is applied vertically upwards now time period is T_(2). The value of (T_(2))/(T_(1)) is (g = 10 m/s^(2))

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