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A bob of a simple pendulum of mass 40gm with a positive charge 4 xx 10^(-6)C is oscillating with time period T_1,. An electric field of intensity 3.6xx10^4 N/c is applied vertically upwards now time period is T_2. The value of is (g = 10m//s^2) |
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Answer» `0.16` |
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