InterviewSolution
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InterviewSolution
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A bob of mass M is suspended by a massless string of length L. The horizonta velocity v at position A is just sufficient to make it reach the point B. The angle `theta` at which the speed of the bob is half of that at A, satisfies A. (a) `theta=pi/4`B. (b) `pi/4ltthetaltpi/4`C. (c) `pi/2ltthetalt(3pi)/(4)`D. (d) `(3pi)/(4)ltthetaltpi` |
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Answer» Correct Answer - D `v=sqrt(5gL)` `(v/2)^2=v^2-2ghimpliesh=L(1-costheta)` Solving the three equations, we get `cos theta=7/8` or `theta=cos^-1(-7/8)=151^@` |
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