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A body cools at the ratio of 1.2^(@)C//min when its temperature is more than that of the surrounding by 40^(@)C. The rate of cooling of the body when its temperature is more than that of surrounding by 25^(@)C will be |
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Answer» `0.75^(@)C`/MIN `(R_(2))/(R_(1))=((theta_(2)-theta_(0)))/((theta_(1)-theta_(0)))=(25)/(40)=(5)/(8)` `R_(2)=0.75`. |
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