A body cools from `50^(@)C` to `46^(@)C` in 5 minutes and to `40^(@)C` in the next 10 minutes. The surrounding temperature is :A. `30^(@)C`B. `28^(@)C`C. `36^(@)C`D. `32^(@)C`

A body cools from `50^(@)C` to `46^(@)C` in 5 minutes and to `40^(@)C`

1.	A body cools from `50^(@)C` to `46^(@)C` in 5 minutes and to `40^(@)C` in the next 10 minutes. The surrounding temperature is :A. `30^(@)C`B. `28^(@)C`C. `36^(@)C`D. `32^(@)C`
Answer» Correct Answer - A `(d theta)/(dt)=K(theta_(av)-theta_(0))` `(4)/(5)=K(48-theta_(0))` . .. (i) `(6)/(10)=K(43-theta_(0))` . .. (ii) `(4)/(5)xx(10)/(6)=((48-theta_(0)))/((43-theta_(0)))` `(4)/(3)=((48-theta_(0)))/((43-theta_(0)))` After solving, `theta_(0)=30^(@)C`.

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A body cools from `50^(@)C` to `46^(@)C` in 5 minutes and to `40^(@)C` in the next 10 minutes. The surrounding temperature is :A. `30^(@)C`B. `28^(@)C`C. `36^(@)C`D. `32^(@)C`

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