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A body cools from 60^(@)C to 52^(@)C in five minutes. What will be further fall in temperature in the next five minutes? If the temperature of the surrounding is 28^(@)C |
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Answer» `4^(@)C` `(8)/(5)=k(56-28)`.. .(i) `(52-theta)/(5)=k((52+theta)/(2)-28)`. . . (II) `(52-theta)/(8)=((52+theta-56))/(2xx28)` `theta=46` `d theta=52-46=6^(@)C ` |
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