1.

A body cools from 60^(@)C to 52^(@)C in five minutes. What will be further fall in temperature in the next five minutes? If the temperature of the surrounding is 28^(@)C

Answer»

`4^(@)C`
`6^(@)C`
`8^(@)C`
`2^(@)C`

SOLUTION :`((d theta)/(DT))=k(theta_(AV_-theta_(0))`
`(8)/(5)=k(56-28)`.. .(i)
`(52-theta)/(5)=k((52+theta)/(2)-28)`. . . (II)
`(52-theta)/(8)=((52+theta-56))/(2xx28)`
`theta=46`
`d theta=52-46=6^(@)C `


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