A body cools in 7 minutes from `60^(@)C` to `40^(@)C`. What will be its temperature after the next 7 minutes? The temperature of the surroundings is `10^(@)C`.A. `32^(@)C`B. `28^(@)C`C. `20^(@)C`D. `25^(@)C`

A body cools in 7 minutes from `60^(@)C` to `40^(@)C`. What will be it

1.	A body cools in 7 minutes from `60^(@)C` to `40^(@)C`. What will be its temperature after the next 7 minutes? The temperature of the surroundings is `10^(@)C`.A. `32^(@)C`B. `28^(@)C`C. `20^(@)C`D. `25^(@)C`
Answer» Correct Answer - B `(d theta)/(dt)=k(theta_(AV)-theta_(0))` `(20)/(7)=k(50-10)` . . (i) `(40-theta)/(7)=k((40+theta)/(2)-10)` . . . (ii) Dividing equation (ii) by (i) `(40-theta)/(20)=(40+theta-20)/(2xx40)` `4(40-theta)=theta+20` `5 theta=160-20` `theta=(140)/(5)=28^(@)C`.

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A body cools in 7 minutes from `60^(@)C` to `40^(@)C`. What will be its temperature after the next 7 minutes? The temperature of the surroundings is `10^(@)C`.A. `32^(@)C`B. `28^(@)C`C. `20^(@)C`D. `25^(@)C`

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