1.

A body falling with a speed of 2 ms-strikes the floor and rebounds with a speed of 1 ms. The loss of energy is:

Answer»

0.125
0.25
0.4
0.75

Solution :Here, LOSS in K.E.=`1/2M[v_1^2-v_2^2]`
=`1/2m[(2)^2-1^2]=3/2m`.
Initial energy=`1/2mxx(2)^2=2m`
% AGE loss=`(3/2m)/(2m)xx100=75%`


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