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A body falls from a heighth = 200 m. The ratio of distance travelled in each 2, during != 0 to 6 second of the journey is: |
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Answer» `1:4:9` Since body starts from rest u=0 After 2 s the distance TRAVELLED is `s_(2)=(1)/(2)xxgxx(2)^(2)=2g` After 4s, `s_(4)=(1)/(2)xxgxx(4)^(2)=8g` After 6s ,`s_6=(1)/(2)xxgxx(6)^(2)=18g` Distance travellled in FIRST 2 `s=d_1=2g` Distance travelled in next `2s=d_2=(8-2)g=6g` Distance travellled in last `2s=d_3(18-8)g=10g` `:. d_1 :d_2 : d_3 : : 2g :6 g: 10 g` `therefore1 : 3: 5`. |
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