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A body falls from rest. In the last second of its fall, it covers half of the total distance then the total time of its fall is |
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Answer» `(2-sqrt(2))s` s/2 =0 +g/2(2n-1) s=g(2n-1)=9.8(2n-1) Also `s=0+(1)/(2)gn^(2)=4.9n^(2)` `:. 9.8(2n-1)=4.9n^(2)` or `n^2 -4n+2=0` Solving the quadrtic EQUATION, `n=(2+sqrt(2))` second. |
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