A body falls on the ground from a height of 10 metre and rebounds to a height of 2.5 m. The ratio of the velocity of the body before collision to the velocity of the body after collision is:

A body falls on the ground from a height of 10 metre and rebounds to a

1.	A body falls on the ground from a height of 10 metre and rebounds to a height of 2.5 m. The ratio of the velocity of the body before collision to the velocity of the body after collision is:
Answer» `2:1` `1:2` `4:1` `3:1` Solution :Here HEIGHT of FALL `h_1=10m` and height of rebound `h_2=25m` LET the velocity of strike be `v_1` and that of rebound be `v_2` then `(v_1)/(v_2)=sqrt((2gh)/(2gh_2))=sqrt((h_1)/(h_2))` =`sqrt((10)/(2.5))=2//1` `v_1:v_2: :2:1`

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A body falls on the ground from a height of 10 metre and rebounds to a height of 2.5 m. The ratio of the velocity of the body before collision to the velocity of the body after collision is:

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