InterviewSolution
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InterviewSolution
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A body has maximum range `R_(1)` when projected up the inclined plane. The same body when projected down, the inclined plane. It has maximum range `R_(2)`. Find its maximum horizontal range. Assume the equal speed of projection in each case and the body is projected onto the gretest slope. A. `R=(2R_(1)R_(2))/(R_(1)-R_(2))`B. `R=(2R_(1)R_(2))/(R_(1)+R_(2)`C. `R=(R_(1)R_(2))/(R_(1)-R_(2))`D. `R=(4R_(1)R_(2))/(R_(1)+R_(2))` |
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Answer» Correct Answer - c For upward projecton, `R_("max")=(V_(0)^(2))/(g(1-sinbeta))=R_(1)` .............(i) For downward projection `R_("min")=(v_(0)^(2))/(g(1+sin beta))=R_(2)` ..........(ii) |
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