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A body is completely submerged inside the liquid. It is in equilibrium and in rest condition at certain temperature. It gamma_(L) volumetric expansion coefficient of liquid alpha_(s) = linear expansion coefficient by of body. It we increases temperature by Delta theta amount than find (a) New thrust force if initial volume of body is V_(0) and density of liquid is d_(0). (b) Relation between alpha_(s) and gamma_(L) so body will (i) move upward (ii) down ward (iii) remains are rest |
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Answer» Solution :(a) `v_(0)d_(0) g((1+3alpha_(s)DELTA THETA)/(1+gamma_(L) Delta theta))` (b) (i) `gamma_(L) lt 3 alpha_(s)` (ii) `gamma_(L) gt 3alpha_(s)` (iii) `gamma_(L) =3alpha_(s)` |
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