1.

A body is dropped from a certain height. At the instant it loses P.E.U. It acquires a velocity 'v' the mass of the body is :

Answer»

`U^(2)//2V`
`2V//U`
`2V//U^(2)`
`2U//V^(2)`

SOLUTION :GAIN in K.E. = LOSS in p.E.
`:. 1/2mv^(2)=U`
`:. M=(2U)/(V^(2))`


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