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A body is dropped from a height of 100m. At what height the velocity of the body will be equal to one half of the velocity when it hits the ground ? |
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Answer» SOLUTION :`1/2mV_0^2=1/2mV^2-1/2mV_e^2 V_0^2=(3V_e)^2-V_e^2therefore V_0=SQRT(9V_e^2-V_e^2)=sqrt(8V_e^2)=2sqrt2V_e` |
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