Saved Bookmarks
| 1. |
A body is executing S.H.M. with maximum velocity of 16 cm/s and amplitude 4 cm. What is it's maximum acceleration ? |
|
Answer» Solution :`v_max=AOMEGA 16 = a omega` `1 =4xxomega` `THEREFORE omega=4` `A_max=aomega^2=(aomega)xxomega=v_maxomega` `=16xx4=64 cm//s^2` |
|