1.

A body is executing S.H.M. with maximum velocity of 16 cm/s and amplitude 4 cm. What is it's maximum acceleration ?

Answer»

Solution :`v_max=AOMEGA 16 = a omega`
`1 =4xxomega`
`THEREFORE omega=4`
`A_max=aomega^2=(aomega)xxomega=v_maxomega`
`=16xx4=64 cm//s^2`


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