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A body is falling under gravity . When it loses a gravitational potential energy `U`, its speed is`v`. The mass of the body shell beA. `2U//v^(2)`B. `2v//U^(2)`C. `2v//U`D. `U^(2)//2v` |
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Answer» Correct Answer - A `U_(i)+0=U_(f)+1/2 mv^(2)` `U_(i)-U_(f)=1/2 mv^(2)` `U=1/2 mv^(2)` `m=(2U)/(v^(2))` |
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