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A body is mass `300 kg` is moved through `10 m` along a smooth inclined plane of inclination angle `30^@`. The work done in moving (in joules) is `(g = 9.8 ms^(-2))`.A. 4900B. 9800C. 14700D. 2450 |
Answer» Correct Answer - D (d) We know that, `W=mg cos theta xxs` `W=300xx9.8xxcos30^(@)xx10` `=300xx9.8xx(sqrt3)/(2)xx10=2450J` |
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