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A body is orbiting around earth at a mean radius which is two times as greater as the parking orbit of a satellite, the period of body isA. 4daysB. 16 daysC. `2sqrt(2)`daysD. 64 days |
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Answer» Correct Answer - C From kepler third law of planetary motion `T^(2) prop r^(3)` Given `T_(1)=1` day (geosatationary) `therefore (T_(1))/(T_(2))^(2)=(r_(1))/(r_(2))^(3)` `rarr T_(2)^(2)=(r_(2))/(r_(1))^(3)xxT_(1)^(2)=(2r)/(R )^(3)xx1=8` `rarr T_(2)=2sqrt(2)`days |
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