InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
A body is projected at an angle of `30^(@)` with the horizontal and with a speed of `30ms^(-1)`. What is the angle with the horizontal after 1.5 second? `(g=10ms^(-2))`A. `0^(@)`B. `30^(@)`C. `60^(@)`D. `90^(@)` |
|
Answer» Correct Answer - a The time of light is given by `T=(2u sin theta)/g=(2xx30xx1)/(10xx2)=3 sec` Thus, after 1.5 sec the body is at the highest point. As the direction ofmotion is horizontal after 5 sec the angle with the horizontal is `0^(@)`. |
|