A body is projected at an angle such that K.E. at the highest point is reduced to half the energy at point of projection. The angle of projection is :

A body is projected at an angle such that K.E. at the highest point is

1.	A body is projected at an angle such that K.E. at the highest point is reduced to half the energy at point of projection. The angle of projection is :
Answer» 30° 75° 45° 60° Solution :We know that K.E. at highest point = `E cos^(2)theta` where E is INITIAL energy. `:. Ecos^(2)theta=1/2E` `costheta=1/sqrt(2)IMPLIES theta=45^@`

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A body is projected at an angle such that K.E. at the highest point is reduced to half the energy at point of projection. The angle of projection is :

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