InterviewSolution
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InterviewSolution
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A body is projected up a smooth inclined plane with velocity V from the point A as shown in the figure. The angle of inclination is `45^(@)` and the top is connected to a well of diameter 40m. If the body just manages to across the well, what is the value of V? Length of inclined plane is `20sqrt(2)m`. A. `40ms^(-1)`B. `40 sqrt(2) ms^(-1)`C. `20ms^(-1)`D. `20 sqrt(2) ms^(-1)` |
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Answer» Correct Answer - d Angle of projection form B is `45^(@)`. As the body is able to cross the well of diameter 40m, hence or `R=(v^(2))/g or v=sqrt(gR)` `v=sqrt(10xx40)=20ms^(-1)` On the inclined plane, the retardation is: `gsin alpha=g sin 45^(@)=10/(sqrt(2))ms^(-2)` Using `v^(2)-u^(2)=2ax` `(20)^(2)-u^(2)=2xx(-10/(sqrt(2)))xx20sqrt(2)` `u=20sqrt(2)ms^(-1), i.e, V=20sqrt(2)ms^(-1)` |
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