1.

A body is released at a distance far away from the surface of the earth. Calculate its speed when it is near the surface of earth. Given `g=9.8ms^(-2)` radius of earth `R=6.37xx10^(6)m`

Answer» Conservation of energy implies
`0+0=1/2mv^(2)-(GMm)/R`
`v=sqrt((2GM)/R)=sqrt((2(R^(2)g))/R)`
`=sqrt(2Rg)~~11.2xx10^(3)ms^(-1)`


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