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A body is released from a great height and falls freely under gravity vertically towards eurth. Another body is released from the same height exactly one second later from the same point. Separation between the two after 2 second of release of the second body is : |
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Answer» 24.5 m For SECOND body `h_2=(1)/(2)g(t-1)^(2)` For SEPARATION `h_1-h_2=(1)/(2)[t^(2)=(t-1)^(2)]` HENCE t=(2+1)=3s `:. H_1-h_2=(9.8)/(2)[9-4]=24.5m` |
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