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A body is released from the top of a building of height 19.6 m. Find the velocity with which the body hits the ground. |
Answer» Data: h = 19.6 m, u = 0 m/s, g = 9.8 m/s2, s = 19.6 m, v = ? v2 = u2 + 2 gs . = 2 gs …..(as u = 0 m/s) = 2 × 9.8 m/s2 × 19.6 m = (19.6 m/s)2 ∴ v = 19.6 m/s (downward velocity) The velocity with which the body hits the i ground = 19.6 m/s (downward). |
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