1.

A body is released from the top of a tower of height metre. It takes time T seconds to reach the ground. Where is the body at time T/2seconds?

Answer»

At `H/2` m from the ground
At `h/4` m from the ground
At `3h/4` m from the ground
Depend upon mass and volume of the body

Solution :`h=(1)/(2) g t^(2) implies T^(2)=(2H)/(g)`
In timeT/2`h=(1)/(2)g. (T^(2))/(4)=(1)/(2)g.(1)/(4),(2h)/(g)=(h)/(4)` from top
`:.` Body is at `(h-(h)/(4))=(3h)/(4)` from BOTTOM


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