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A body is thrown up with a velocity 10% more than the escape velocity v_(e ). When the body escapes the gravitational pull of the earth the velocity still left in the body is : |
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Answer» `0.1v_(e )` `therefore` Velocity of BODY after escaping the gravitational fieldis `v=SQRT(x^(2)-1) "" v_(e )=sqrt(((121)/(100)-1))-v_(e )=sqrt((21)/(100))v_(e )` `=0.458 v_(e )` So CORRECT choice is (c ). |
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