1.

A body is thrown up with a velocity 10% more than the escape velocity v_(e ). When the body escapes the gravitational pull of the earth the velocity still left in the body is :

Answer»

`0.1v_(e )`
`0.229 v_(e )`
`0.458 v_(e )`
`0.20 v_(e )` .

Solution :`V=v_(e )+(10)/(100)v_(e )=(11)/(10)v_(e )`
`therefore` Velocity of BODY after escaping the gravitational fieldis
`v=SQRT(x^(2)-1) "" v_(e )=sqrt(((121)/(100)-1))-v_(e )=sqrt((21)/(100))v_(e )`
`=0.458 v_(e )`
So CORRECT choice is (c ).


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