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A body moves along a circle of radius 1 m with a constant kinetic energy 25 j . Then force acting on it is `A. 25 NB. 50 NC. 10 ND. 5 N

Answer» Correct Answer - B
`KE=(1)/(2) F r `
`therefore F =(2KE)/(r)=(2xx25)/(1)=50N`.


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