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A body moves along the curved path of a quartercircle. Calculate the ratio of distance to displacement:

Answer» <p>Body moves in quarter part of circle.So, distance will be quarter of circumference of circle=2πr/4=πr/2Displacement will be shortest distance .From the figure : AB is the Displacement .It forms a right angle traingle.AB² =displacement=Hypotenuse=√(r²+r²)=√2r²=r√2</p><p>Ratio of distance to displacement =πr/2xr√2=π/2√2=π/2√2=22/√2x(2x7)=11/√2x7</p><p>∴ Ratio of Distance to displacement is 11 :√2(7)</p> <p>thanks </p>


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