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A body of mass 0.1 kgperforming linear SHM experiences a restoring force of 1 N when its displacement from the mean position is 5 cm. Find (i) the force constant (ii) the period of SHM (iii) the acceleration of the body, when its displacement from the mean position is 1 cm./ |
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Answer» Solution :DATA : , m= 0.1 kg , F=1 , N x =5 `xx 10^(-2) m, x_(1) = 10^(-2) `m (i) F= kx The force constant= ` K = F/x = 1/(5xx 10^(-2)) = 20 ` N/m (ii) The period of the motion ` T = 2 pi sqrt(m/k) =2pi sqrt(0.1/20) = (2pi)/(10sqrt2) = (6.284)/(14.14)` = 0.4444 s The magnitude of the acceleration . LTBR. ` a = omega^(2) x= ((2pi)/T)^(2) x= (4pi(10^(-2)))/(4pi^(2)//200) = 2m//s^(2)` |
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