InterviewSolution
Saved Bookmarks
| 1. |
A body of mass 0.8 kg has intial velocity `(3hati-4hatj) ms^(-1)` and final velocity `(-6hatj+2hatk) ms^(-1)`. Find change in kinetic energy of the body? |
|
Answer» Change in kinetic energy `DeltaKE=(1)/(2)mv_(f)^(2)-(1)/(2)mv_(i)^(2)` where, `v_(f)=sqrt(6^(2)+4^(2))=sqrt(40)` and `v_(i)=sqrt(3^(2)+4^(2))=sqrt(25)` `(1)/(2)xx0.8[sqrt(40))^(2)-(sqrt(25)^(2))]` `=0.4[40-25]=0.4(15)=6 J` |
|